(i) A's average number of points = \(\frac{14 + 16 + 10 + 10 }{4}\) = \(\frac{50}{4}\) = 12.5
(ii) To find the mean number of points per game for C, we will divide the total points by 3 because C played 3 games.
(iii) Mean of B's score = \(\frac{0 + 8 + 6 + 4 }{4}\) = \(\frac{18}{4}\) = 4.5
(iv) The best performer will have the greatest average of all. Now we can observe that the average of A is 12.5 which is more than that of B and C. Therefore, A is the best performer among these three.
Write equations for the following statements:
(i) The sum of numbers x and 4 is 9.
(ii) 2 subtracted from y is 8.
(iii) Ten times a is 70.
(iv) The number b divided by 5 gives 6.
(v) Three-fourth of t is 15.
(vi) Seven times m plus 7 gets you 77.
(vii) One-fourth of a number x minus 4 gives 4.
(viii) If you take away 6 from 6 times y, you get 60.
(ix) If you add 3 to one-third of z, you get 30