(i) A's average number of points = \(\frac{14 + 16 + 10 + 10 }{4}\) = \(\frac{50}{4}\) = 12.5
(ii) To find the mean number of points per game for C, we will divide the total points by 3 because C played 3 games.
(iii) Mean of B's score = \(\frac{0 + 8 + 6 + 4 }{4}\) = \(\frac{18}{4}\) = 4.5
(iv) The best performer will have the greatest average of all. Now we can observe that the average of A is 12.5 which is more than that of B and C. Therefore, A is the best performer among these three.