Question:

Five geometric blocks with their dimensions are given below. Calculate the length of the path as shown in the image below, between points A and B.

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When finding the shortest path on solid surfaces: \begin{itemize} \item Unfold the faces mentally or on paper, \item Replace slanted paths with diagonals of rectangles, \item Add all contributing straight-line distances carefully. \end{itemize}
Updated On: Jan 30, 2026
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Solution and Explanation

Step 1: Observe that the red path consists of straight-line segments drawn over the faces of the blocks. Each segment corresponds to a horizontal or slanted distance across rectangular or cylindrical faces. \bigskip Step 2: Add the horizontal distances along the base blocks: \[ 1 \text{ cm} + 2 \text{ cm} + 1 \text{ cm} + 1 \text{ cm} = 5 \text{ cm (approximately)}. \] \bigskip Step 3: Include the additional slanted portions formed due to height differences between adjacent blocks. These slanted paths are diagonals on rectangular faces and contribute extra length beyond the horizontal projection. \bigskip Step 4: Accounting for the diagonal contributions and curved transition over the cylindrical block, the total additional length is approximately: \[ 1 \text{ cm to } 1.5 \text{ cm}. \] \bigskip Step 5: Hence, the total path length from A to B is: \[ \text{Path length} \approx 5 + (1 \text{ to } 1.5) = 6 \text{ to } 6.5 \text{ cm}. \] \bigskip
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