Question:

Five friends agree to split the cost of a lunch equally. If one of the friends does not attend the lunch, the remaining four friends would each have to pay an additional $6. What is the cost of the lunch?

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There's a faster, more logical way to solve this. The extra money paid by the 4 remaining friends must cover the share of the 5th friend who didn't attend. Each of the 4 friends paid an extra $6, so they collectively paid an extra \(4 \times $6 = $24\). This $24 is exactly the share of the absent friend. If one person's share was $24, and there were originally 5 people, the total cost is \(5 \times $24 = $120\).
Updated On: Oct 3, 2025
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The Correct Option is

Solution and Explanation

Step 1: Understanding the Concept:
This is a word problem that can be solved by setting up an algebraic equation representing the two scenarios (splitting the cost among 5 friends vs. 4 friends).
Step 2: Key Formula or Approach:
Let \(C\) be the total cost of the lunch.
The original cost per person (with 5 friends) is \(\frac{C}{5}\).
The new cost per person (with 4 friends) is \(\frac{C}{4}\).
The problem states that the new cost is $6 more than the original cost. We can write this as an equation: \(\frac{C}{4} = \frac{C}{5} + 6\).
Step 3: Detailed Explanation:
We have the equation: \[ \frac{C}{4} = \frac{C}{5} + 6 \] To solve for \(C\), we should first eliminate the denominators. The least common multiple (LCM) of 4 and 5 is 20. Multiply both sides of the equation by 20: \[ 20 \left( \frac{C}{4} \right) = 20 \left( \frac{C}{5} + 6 \right) \] Distribute the 20 on the right side: \[ 5C = 20 \left( \frac{C}{5} \right) + 20(6) \] \[ 5C = 4C + 120 \] Now, isolate \(C\) by subtracting \(4C\) from both sides: \[ 5C - 4C = 120 \] \[ C = 120 \] So, the total cost of the lunch is $120.
Step 4: Final Answer:
The total cost of the lunch is $120. This corresponds to option (E).
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