(i) Radius of the cone, r = 6 cm
Height of the cone, h = 7 cm
Volume of the cone = \(\frac{1}{3}\text{πr²h}\)
=\(\frac{1}{3}\) × \(\frac{22}{7}\) × 6 cm × 6 cm × 7 cm
= 264 cm³
(ii) Radius of the cone, r = 3.5 cm
Height of the cone, h = 12 cm
Volume of the cone = \(\frac{1}{3}\pi r²h\)
= \(\frac{1}{3}\) × \(\frac{22}{7}\) × 3.5 cm × 3.5 cm × 12 cm
= 154 cm³
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?