We are asked to find the value of \( (3 + \sqrt{8})^5 + (3 - \sqrt{8})^5 \).
Step 1: Notice that this expression is a sum of the powers of two conjugates. We can use the binomial theorem to expand each term:
\[
(3 + \sqrt{8})^5 = \sum_{k=0}^{5} \binom{5}{k} 3^{5-k} (\sqrt{8})^k
\]
\[
(3 - \sqrt{8})^5 = \sum_{k=0}^{5} \binom{5}{k} 3^{5-k} (-\sqrt{8})^k
\]
Step 2: Add the two expansions, and note that the odd powers of \( \sqrt{8} \) cancel out, leaving only the even powers. After simplifying the remaining terms, we get the value \( 6726 \).
Thus, the correct answer is 6726.