(i) Radius (r) of sphere = 10.5 cm
Surface area of sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7}\) × (10.5cm)2
= 1386 cm2
Therefore, the surface area of a sphere having radius 10.5cm is 1386 cm2 .
(ii) Radius(r) of sphere = 5.6 cm
Surface area of sphere = \(4\pi r^2\)
= 4 × \(\frac{22}{7} \)× (5.6cm)2
= 394.24 cm2
Therefore, the surface area of a sphere having radius 5.6 cm is 394.24 cm2 .
(iii) Radius (r) of sphere = 14 cm
Surface area of sphere =\( 4\pi r^2\)
= 4 × \(\frac{22}{7}\) × (14cm)2
= 2464 cm2
Therefore, the surface area of a sphere having radius 14 cm is 2464 cm2 .
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?