The given G.P. is \(\sqrt{7},\sqrt{21},3\sqrt{7},\) ...
Here, a = \(\sqrt{7}\)
r = \(\frac{\sqrt{21}}{\sqrt{7}}=\sqrt{3}\)
Sn = \(\frac{a(1-r^n)}{1-r}\)
∴ Sn = \(\frac{\sqrt7[1-({\sqrt3})n]}{1-\sqrt3}\)
= \(\frac{\sqrt{7}[1-(\sqrt{3})n]}{1-\sqrt{3}}\times\frac{1+\sqrt{3}}{1+\sqrt{3}}\) (By rationalizing)
= \(\frac{\sqrt{7}(1+\sqrt{3})[1-(\sqrt{3}n]}{1-3}\)
= \(-\frac{\sqrt{7}(1+\sqrt{3})}{2[\frac{1-(3)n}{2}]}\)
= \(\frac{\sqrt{7}(1+\sqrt{3})}{2\bigg[\frac{(3)n}{2}{-1}\bigg]}\)
Let \( 0 < z < y < x \) be three real numbers such that \( \frac{1}{x}, \frac{1}{y}, \frac{1}{z} \) are in an arithmetic progression and \( x, \sqrt{2}y, z \) are in a geometric progression. If \( xy + yz + zx = \frac{3}{\sqrt{2}} xyz \), then \( 3(x + y + z)^2 \) is equal to ____________.
Give reasons for the following.
(i) King Tut’s body has been subjected to repeated scrutiny.
(ii) Howard Carter’s investigation was resented.
(iii) Carter had to chisel away the solidified resins to raise the king’s remains.
(iv) Tut’s body was buried along with gilded treasures.
(v) The boy king changed his name from Tutankhaten to Tutankhamun.