Let the radius of the sphere be r.
Surface area of sphere = 154
So, \(4\pi r^2 = 154\ cm^2 \)
r2 = \(\frac{154}{4\pi}\)
r2 = \(\left(\frac{154}{4}\right) \left(\frac{7}{22}\right)\)
r2 = \(\frac{\text{(154 × 7) }}{\text{ (4 × 22)}}\)
r2 = \((\frac{49}{4})\)
r = (\(\frac{7}{2}\)) = 3.5 cm
Therefore, the radius of the sphere whose surface area is 154 cm2 is 3.5 cm.
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.