Question:

Find the maximum value of f(x) = (1 / (4x2 + 2x + 1)).

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To find the maximum or minimum value of a rational function, differentiate the function, set the first derivative equal to zero, and check the behavior of the function at critical points.
Updated On: Apr 23, 2025
  • \( \frac{3}{4} \)
  • \( \frac{4}{3} \)
  • \( \frac{1}{3} \)
  • None of these
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The Correct Option is B

Solution and Explanation

To find the maximum value of \( f(x) = \frac{1}{4x^2 + 2x + 1} \), we first differentiate \( f(x) \). 1. The function is \( f(x) = \frac{1}{4x^2 + 2x + 1} \). 2. Differentiate \( f(x) \) with respect to \( x \) using the chain rule: \[ f'(x) = \frac{- (8x + 2)}{(4x^2 + 2x + 1)^2} \] 3. Set \( f'(x) = 0 \) to find critical points. This occurs when the numerator is zero, i.e., \( 8x + 2 = 0 \), solving for \( x \), we get \( x = -\frac{1}{4} \). 4. To confirm whether this is a maximum, check the second derivative or use the nature of the function. We find that \( f(x) \) attains its maximum at \( x = -\frac{1}{4} \), and the maximum value is \( \frac{4}{3} \).
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