Question

Find the final product for the reaction: \[ \text{C}_6\text{H}_5\text{CHO} + \text{CH}_3\text{CO}\text{C}_6\text{H}_5 \xrightarrow{\text{OH}^-, 293 K} \text{Product} \]

• A. \(\text{C}_6\text{H}_5\text{CH}=\text{CH}\text{C}_6\text{H}_5 \)
• B. \(\text{C}_6\text{H}_5\text{CH}=\text{CH}\text{C}_6\text{H}_5 \text{OH} \)
• C. \(\text{C}_6\text{H}_5\text{OH} \)
• D. \(\text{C}_6\text{H}_5\text{CH}_2\text{C}_6\text{H}_5 \)

Hint:

Aldol condensation reactions can produce conjugated enones or enals, which are important intermediates in organic synthesis.

Answer 1

The Correct Option is A

The given reaction is a condensation reaction between benzaldehyde (\(C_6H_5\)CHO) and acetophenone (\(CH_3CO\)\(C_6H_5\)), known as the Aldol condensation. This reaction proceeds under basic conditions (in the presence of \(OH^-\)) and at 293 K, forming a conjugated enone product. The product formed is stilbene (\(C_6H_5\)CH=CH\(C_6H_5\)), which is an $\alpha$,$\beta$-unsaturated carbonyl compound. Thus, the correct answer is Option (A).