Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines \(x - 7y+ 5 = 0\) and \(3x + y = 0.\)
Solution and Explanation
The equation of any line parallel to the y-axis is of the form
\(x = a … (1) \)
The two given lines are
\(x - 7y + 5 = 0 … (2) \)
\(3x + y = 0 … (3)\)
On solving equations (2) and (3), we obtain
\(x = \frac{-5}{22}\) and \(y = \frac{15}{22}\)
Therefore\(,(\frac{-5}{22},\frac{15}{22})\) is the point of intersection of lines (2) and (3).
Since line \(x = a\) passes through point \((\frac{-5}{22},\frac{15}{22})\), \(a=\frac{-5}{22}\)
Thus, the required equation of the line is \(x=\frac{-5}{22}.\)
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Concepts Used:
Straight lines
A straight line is a line having the shortest distance between two points.
A straight line can be represented as an equation in various forms, as show in the image below:
The following are the many forms of the equation of the line that are presented in straight line-
1. Slope – Point Form
Assume P0(x0, y0) is a fixed point on a non-vertical line L with m as its slope. If P (x, y) is an arbitrary point on L, then the point (x, y) lies on the line with slope m through the fixed point (x0, y0) if and only if its coordinates fulfil the equation below.
y – y0 = m (x – x0)
2. Two – Point Form
Let's look at the line. L crosses between two places. P1(x1, y1) and P2(x2, y2) are general points on L, while P (x, y) is a general point on L. As a result, the three points P1, P2, and P are collinear, and it becomes
The slope of P2P = The slope of P1P2 , i.e.
\(\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\)
Hence, the equation becomes:
y - y1 =\( \frac{y_2-y_1}{x_2-x_1} (x-x1)\)
3. Slope-Intercept Form
Assume that a line L with slope m intersects the y-axis at a distance c from the origin, and that the distance c is referred to as the line L's y-intercept. As a result, the coordinates of the spot on the y-axis where the line intersects are (0, c). As a result, the slope of the line L is m, and it passes through a fixed point (0, c). The equation of the line L thus obtained from the slope – point form is given by
y – c =m( x - 0 )
As a result, the point (x, y) on the line with slope m and y-intercept c lies on the line, if and only if
y = m x +c