Question:

Find the equation of the hyperbola satisfying the give conditions: Vertices (±2, 0), foci (±3, 0)

Updated On: Oct 23, 2023
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Solution and Explanation

Vertices (±2, 0), foci (±3, 0) 
Here, the vertices are on the x-axis. 

Therefore, the equation of the hyperbola is of the form \(\frac{x^2}{a^2} –\frac{ y^2}{b^2} = 1\)
Since the vertices are (±2, 0), a = 2. 
Since the foci are (±3, 0), c = 3. 

We know that \(a ^2 + b^ 2 = c^ 2.\)

\(∴ 2^2 + b^2 = 3^2\)
\(b^2 = 9 – 4 = 5\)

∴ The equation of the hyperbola is \(\frac{x^2}{4} –\frac{ y^2}{5} = 1\)

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Concepts Used:

Hyperbola

Hyperbola is the locus of all the points in a plane such that the difference in their distances from two fixed points in the plane is constant.

Hyperbola is made up of two similar curves that resemble a parabola. Hyperbola has two fixed points which can be shown in the picture, are known as foci or focus. When we join the foci or focus using a line segment then its midpoint gives us centre. Hence, this line segment is known as the transverse axis.

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