Find the equation for the ellipse that satisfies the given conditions:Major axis on the x-axis and passes through the points (4,3) and (6,2).
Given that :
The major axis is on the x-axis, and the equation of the ellipse will be of the form \(\dfrac{x^2}{b^2} +\dfrac{y^2}{a^2} = 1 ....(1)\), (where ‘\(a\)’ is the semi-major axis.)
The ellipse passes through points \((4, 3)\) and \((6, 2)\).
Hence,
\(\dfrac{16}{a^2} + \dfrac{9}{b^2} = 1…. (2)\)
\(\dfrac{36}{a^2} + \dfrac{4}{b^2} = 1 …. (3)\)
On solving equations (2) and (3), we obtain \(a^2= 5^2\) and \(b^2= 13\)
Thus, the equation of the ellipse is \(\dfrac{x^2}{5^2} +\dfrac{y^2}{13} = 1\)
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
An ellipse is a locus of a point that moves in such a way that its distance from a fixed point (focus) to its perpendicular distance from a fixed straight line (directrix) is constant. i.e. eccentricity(e) which is less than unity
Read More: Conic Section
The ratio of distances from the center of the ellipse from either focus to the semi-major axis of the ellipse is defined as the eccentricity of the ellipse.
The eccentricity of ellipse, e = c/a
Where c is the focal length and a is length of the semi-major axis.
Since c ≤ a the eccentricity is always greater than 1 in the case of an ellipse.
Also,
c2 = a2 – b2
Therefore, eccentricity becomes:
e = √(a2 – b2)/a
e = √[(a2 – b2)/a2] e = √[1-(b2/a2)]
The area of an ellipse = πab, where a is the semi major axis and b is the semi minor axis.
Let the point p(x1, y1) and ellipse
(x2 / a2) + (y2 / b2) = 1
If [(x12 / a2)+ (y12 / b2) − 1)]
= 0 {on the curve}
<0{inside the curve}
>0 {outside the curve}