Letf(x) = x. Accordingly, f'(1) = \(\lim_{h\rightarrow 0}\)\(\frac{f(1+h)-f(1)}{h}\) = \(\lim_{h\rightarrow 0}\)\(\frac{(1+h)-(1)}{h}\) = \(\lim_{h\rightarrow 0}\)\(\frac{h}{h}\) = \(\lim_{h\rightarrow 0}\) (1) =1 Thus, the derivative of x at x = 1 is 1.