Find the correct combination about the following plots (P,Q and R) for the variation rate of reaction with time.
Q=Reversible;P=Zero order;R=Irreversible
R=Zero order;P=Zero order;R=Irreversible
Q=Irreversible;R=Reversible;P=Zero order
P=Irreversible;Q=Reversible;R=Zero order
P=Reversible;Q=Zero order;R=Irreversible
Plot (P): The rate decreases over time, but it's not a constant rate. The rate starts high and gradually decreases, approaching zero. This suggests a reaction where the rate depends on the concentration of reactants, and as reactants are consumed, the rate slows down. This is characteristic of a first or higher order reaction, not zero-order. Further, there is no reverse reaction so it is irreversible
Plot (Q): This plot clearly shows both forward and backward reaction rates. The rates converge to a point where the forward and backward rates are equal, indicating equilibrium. This is a reversible reaction. It is not zero order, since it is not linear.
Plot (R): The rate is constant until some of it disappears, then remains constant.
This is an odd reaction, but fits the graph for a zero order reaction.
Therefore, the correct combination is (D) P = Irreversible; Q = Reversible; R = Zero order
Let's analyze the given plots (P, Q, and R) for the variation rate of reaction with time to find the correct combination.
Plot P
- The rate of reaction decreases exponentially with time.
- This suggests that the concentration of reactants is decreasing over time, which is typical for an irreversible reaction.
- Conclusion: Plot P corresponds to an irreversible reaction.
Plot Q
- There are two curves: one decreasing and one increasing, which eventually reach equilibrium.
- This indicates that initially, the forward reaction rate is higher and the backward reaction rate is lower. Over time, they become equal.
- This is characteristic of a reversible reaction where the forward and backward reaction rates eventually reach equilibrium.
- Conclusion: Plot Q corresponds to a reversible reaction.
Plot R
- The rate of reaction remains constant over time.
- This is indicative of a zero-order reaction, where the rate is independent of the concentration of reactants.
- Conclusion: Plot R corresponds to a zero-order reaction.
Correct Combination
- P: Irreversible reaction
- Q: Reversible reaction
- R: Zero-order reaction
Hence, the correct combination is:
\[\boxed{P = \text{Irreversible}; Q = \text{Reversible}; R = \text{Zero order}}\]
So the correct Answer is Option 4(D): P=Irreversible;Q=Reversible;R=Zero order
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively:
The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.
Consider the reaction A → B,
Rate of the reaction is given by,
Rate = −d[A]/ dt=+d[B]/ dt
Where, [A] → concentration of reactant A
[B] → concentration of product B
(-) A negative sign indicates a decrease in the concentration of A with time.
(+) A positive sign indicates an increase in the concentration of B with time.
There are certain factors that determine the rate of a reaction: