(i) Radius of the cone, r = 7cm
Slant height of the cone, l = 25cm
Height of the cone, \(h = \sqrt{l² - r²}\)
\(= \sqrt{(25)² - (7)²}\)
\(= \sqrt{625 - 49}\)
\(= \sqrt{576}\)
h = 24 cm
Volume of cone =\( \frac{1}{3}\) \(\pi \)r²h
= \(\frac{1}{3}\) × \(\frac{22}{7}\) × 7 cm × 7 cm × 24 cm
= 1232 cm³
= 1232 × (\(\frac{1}{1000}\)L)
= 1.232 liters
(ii) Height of the cone, h = 7cm
Slant height of the cone, l = 13cm
Radius of the cone, \(r = \sqrt{l² - h²}\)
\(= \sqrt{(13)² - (12)²}\)
\(= \sqrt{169 -144}\)
\(= \sqrt{25}\)
r = 5 cm
Volume of the cone = \(\frac{1}{3}\)\(\pi\)r²h
= \(\frac{1}{3}\) × \(\frac{22}{7}\) × 5 cm × 5 cm × 12 cm
\(= \frac{2200}{7}\) cm³
\(= \frac{2200}{7} × \frac{1}{1000}\ L \)
\(=\frac{ 11}{35}\) litres
(Street Plan) : A city has two main roads which cross each other at the centre of the city. These two roads are along the North-South direction and East-West direction.
All the other streets of the city run parallel to these roads and are 200 m apart. There are 5 streets in each direction. Using 1cm = 200 m, draw a model of the city on your notebook. Represent the roads/streets by single lines. There are many cross- streets in your model. A particular cross-street is made by two streets, one running in the North - South direction and another in the East - West direction. Each cross street is referred to in the following manner : If the 2nd street running in the North - South direction and 5th in the East - West direction meet at some crossing, then we will call this cross-street (2, 5). Using this convention, find:
(i) how many cross - streets can be referred to as (4, 3).
(ii) how many cross - streets can be referred to as (3, 4).