(i) Radius of the cone, r = 7cm
Slant height of the cone, l = 25cm
Height of the cone, \(h = \sqrt{l² - r²}\)
\(= \sqrt{(25)² - (7)²}\)
\(= \sqrt{625 - 49}\)
\(= \sqrt{576}\)
h = 24 cm
Volume of cone =\( \frac{1}{3}\) \(\pi \)r²h
= \(\frac{1}{3}\) × \(\frac{22}{7}\) × 7 cm × 7 cm × 24 cm
= 1232 cm³
= 1232 × (\(\frac{1}{1000}\)L)
= 1.232 liters
(ii) Height of the cone, h = 7cm
Slant height of the cone, l = 13cm
Radius of the cone, \(r = \sqrt{l² - h²}\)
\(= \sqrt{(13)² - (12)²}\)
\(= \sqrt{169 -144}\)
\(= \sqrt{25}\)
r = 5 cm
Volume of the cone = \(\frac{1}{3}\)\(\pi\)r²h
= \(\frac{1}{3}\) × \(\frac{22}{7}\) × 5 cm × 5 cm × 12 cm
\(= \frac{2200}{7}\) cm³
\(= \frac{2200}{7} × \frac{1}{1000}\ L \)
\(=\frac{ 11}{35}\) litres
A driver of a car travelling at \(52\) \(km \;h^{–1}\) applies the brakes Shade the area on the graph that represents the distance travelled by the car during the period.
Which part of the graph represents uniform motion of the car?