Find the area of the region bounded by the parabola y=x2 and y=|x|
The area bounded by the parabola,x2=y and the line,y=|x|,can be represented as
The given area is symmetrical about y-axis.
∴Area OACO=Area ODBO
The point of intersection of parabola,x2=y,and line,y=x,is A(1,1).
Area of ΔOAB=1/2×OB×AB=1/2×1×1=1/2
Area of OBACO=∫10ydx=∫10x2dx=[x3/3]10=1/3
⇒Area of OACO=Area of ΔOAB-Area of OBACO
=1/2-1/3
=1/6
Therefore,required area=2[1/6]=1/3units.
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
Balance Sheet of Chandan, Deepak and Elvish as at 31st March, 2024
Liabilities | Amount (₹) | Assets | Amount (₹) |
---|---|---|---|
Capitals: | Fixed Assets | 27,00,000 | |
Chandan | 7,00,000 | Stock | 3,00,000 |
Deepak | 5,00,000 | Debtors | 2,00,000 |
Elvish | 3,00,000 | Cash | 1,00,000 |
General Reserve | 4,50,000 | ||
Creditors | 13,50,000 | ||
Total | 33,00,000 | Total | 33,00,000 |