Find the area of the region bounded by the curve y2=x and the lines x=1,x=4 and the x-axis
The area of the region bounded by the curve y2= x, the lines, x=1 and x = 4,and the x-axis is the area ABCD.
Area of ABCD =\(\int^4_1ydx\)
=\(\int^4_1\sqrt xdx\)
=\(\bigg[\frac{x^{\frac{3}{2}}}{\frac{3}{2}}\bigg]\)
=\(\frac{2}{3}\bigg[(4)^{\frac{3}{2}}-(1)^{\frac{3}{2}}\bigg]\)
=\(\frac{2}{3}\)[8-1]
=\(\frac{14}{3}\) units
What is the Planning Process?
The representation of the area of a region under a curve is called to be as integral. The actual value of an integral can be acquired (approximately) by drawing rectangles.
Also, F(x) is known to be a Newton-Leibnitz integral or antiderivative or primitive of a function f(x) on an interval I.
F'(x) = f(x)
For every value of x = I.
Integral calculus helps to resolve two major types of problems: