Let the height of the pole be $h$ and the length of its shadow be $s = \sqrt{3}h$. Let $\theta$ be the angle of elevation of the Sun. From right triangle formed by the pole and its shadow,
\[
\tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{\sqrt{3}h} = \frac{1}{\sqrt{3}}
\]
Using the standard trigonometric values,
\[
\tan 30° = \frac{1}{\sqrt{3}} \implies \theta = 30°
\]