Find bond order; N2 +, N2 - , N2 +2, CO. Arrange the given molecules in increasing order of their acidic strength.
To determine the bond order of each molecule, we need to examine the molecular orbital diagram for each species. The bond order is calculated by taking the difference between the number of bonding electrons and the number of anti-bonding electrons and dividing it by 2.
N2+: In N2+, one electron is removed from the antibonding π*2p orbital, resulting in a bond order of (5 - 2) / 2 = 1.5.
N2-: In N2-, an additional electron is added to the antibonding π*2p orbital, resulting in a bond order of (5 - 4) / 2 = 0.5.
N2+2: N2+2 does not exist as a stable molecule since it requires four additional electrons, which is highly unfavorable.
CO: CO has a triple bond between carbon and oxygen. The molecular orbital diagram for CO shows that there are 10 bonding electrons and 6 antibonding electrons. Therefore, the bond order is (10 - 6) / 2 = 2.
Now, let's arrange the molecules in increasing order of their acidic strength:
N2- < N2+ < CO < N2+2
In terms of increasing acidic strength, the order is: N2-, N2+, CO, N2+2.
List - IMolecule | List - IIBond enthalpy (kJ mol-1) |
---|---|
(A) HCl | (I) 435.8 |
(B) N2 | (II) 498 |
(C) H2 | (III) 946.0 |
(D) O2 | (IV) 431.0 |
List-I (Compound / Species) | List-II (Shape / Geometry) |
---|---|
(A) \(SF_4\) | (I) Tetrahedral |
(B) \(BrF_3\) | (II) Pyramidal |
(C) \(BrO_{3}^{-}\) | (III) See saw |
(D) \(NH^{+}_{4}\) | (IV) Bent T-shape |
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.