Question:
Find \(\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \frac{\sin^2x}{1+2^x} \;dx\)
Find \(\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \frac{\sin^2x}{1+2^x} \;dx\)
Updated On: Apr 5, 2024
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{8}\)
- 4π
- \(\frac{\pi}{2}\)
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The Correct Option is A
Solution and Explanation
The correct answer is option (A): \(\frac{\pi}{4}\)
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