Question:

Give four rational numbers equivalent to:
(i)\(\frac{-2}{7}\)
(ii) \(\frac{5}{-3}\)
(iii) \(\frac{4}{9}\)

Updated On: Dec 12, 2023
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

(i) \(\frac{-2}{7}\)
Four rational numbers are
\(=\frac{-2\times2}{7\times2},\frac{-2\times3}{7\times3},\frac{-2\times4}{7\times4},\frac{-2\times5}{7\times5}\)

\(=\frac{-4}{14},\frac{-6}{21},\frac{-8}{28},\frac{-10}{35}\)



(ii) \(\frac{5}{-3}\)
Four rational numbers are
\(=\frac{5\times2}{-3\times2},\frac{5\times3}{-3\times3},\frac{5\times4}{-3\times4},\frac{5\times5}{-3\times5}\)

\(=\frac{10}{-6},\frac{15}{-9},\frac{20}{-12},\frac{25}{-15}\)



(iii)\(\frac{4}{9}\)
Four rational numbers are
\(=\frac{4\times2}{9\times2},\frac{4\times3}{9\times3},\frac{4\times4}{9\times4},\frac{4\times5}{9\times5}\)

\(=\frac{8}{18},\frac{12}{27},\frac{16}{36},\frac{20}{45}\)

Was this answer helpful?
0
0

Questions Asked in CBSE Class VII exam

View More Questions