The stable carbocation formed in the above reaction is
The correct answer is (C) :
Initially
\(CH_3 - CH_2 -C\stackrel{+}{H}_2\)
is formed. On rearrangement
\(CH_3 - C\stackrel{+}{H} - CH_3\)
stable carbocation is formed.
List-I | List-II | ||
A. | ![]() | I. | Br2 in CS2 |
B. | ![]() | II. | Na2CR2O7/H2SO4 |
C. | ![]() | III. | Zn |
D. | ![]() | IV. | CHCl3/NaOH |