\([Fe(CN)_6]^{4-}\) and \([Fe(H_2O)_6]^{2+}\) are of different colours in dilute solutions. Why?
The colour of a particular coordination compound depends on the magnitude of the crystal-field splitting energy, \(Δ\). This CFSE in turn depends on the nature of the ligand. In case of \([Fe(CN)_6]^{4-}\) and \([Fe(H_2O)_6]^{2+}\), the colour differs because there is a difference in the CFSE. Now, \(CN ^{- }\)is a strong field ligand having a higher CFSE value as compared to the CFSE value of water. This means that the absorption of energy for the intra \(d-d\) transition also differs. Hence, the transmitted colour also differs.
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
What is crystal field splitting energy?
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
On the basis of CFT, explain why [Ti(H$_2$O)$_6$]Cl$_3$ complex is coloured? What happens on heating the complex [Ti(H$_2$O)$_6$]Cl$_3$? Give reason.