By the \(\textbf{Remainder Theorem}\), the remainder when \( f(x) \) is divided by \( x - a \) is \( f(a) \).
Here, we divide by \( x - 2 \), so we compute \( f(2) \):
\[ f(2) = 5(2)^4 - 9(2)^3 - 3(2)^2 + 11(2) - 18 \] \[ = 5(16) - 9(8) - 3(4) + 22 - 18 \] \[ = 80 - 72 - 12 + 22 - 18 \] \[ = (80 - 72) = 8,\quad (8 - 12) = -4,\quad (-4 + 22) = 18,\quad (18 - 18) = 0 \]
The correct answer is option (A): \(0\)
Let \( \alpha, \beta \) be the roots of the equation \( x^2 - ax - b = 0 \) with \( \text{Im}(\alpha) < \text{Im}(\beta) \). Let \( P_n = \alpha^n - \beta^n \). If \[ P_3 = -5\sqrt{7}, \quad P_4 = -3\sqrt{7}, \quad P_5 = 11\sqrt{7}, \quad P_6 = 45\sqrt{7}, \] then \( |\alpha^4 + \beta^4| \) is equal to: