Question:

Express the given complex number in the form \(a + ib: [(\dfrac{1}{3}+i\dfrac{7}{3})+(4+i\dfrac{1}{3})]-(-\dfrac{4}{3}+i)\)

Updated On: Oct 18, 2023
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Solution and Explanation

\([(\dfrac{1}{3}+i\dfrac{7}{3})+(4+i\dfrac{1}{3})]-(-\dfrac{4}{3}+i)\)

\((\dfrac{1}{3}+4+\dfrac{4}{3}) +i(\dfrac{7}{3}+\dfrac{1}{3}-1)  \)

\(=\dfrac{17}{3}+\dfrac{5}{3}i \)  (Ans)

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Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.