Step 1: Understand the circuit.
The given circuit consists of two switches \( S_1 \) and \( S_2 \), with their complements \( S_1' \) and \( S_2' \) also involved. The circuit configuration suggests a combination of AND, OR, and NOT logic gates.
Step 2: Assign logic variables.
Let the logic variables be \( S_1 \) for switch 1, \( S_2 \) for switch 2, and \( L \) for the output.
Step 3: Determine the symbolic expression.
Based on the circuit, the expression can be written as:
\[
L = (S_1 \cdot S_2') + (S_1' \cdot S_2)
\]
Where:
- \( S_1 \cdot S_2' \) represents the AND operation between \( S_1 \) and \( S_2' \).
- \( S_1' \cdot S_2 \) represents the AND operation between \( S_1' \) and \( S_2 \).
- The OR operation is denoted by the plus sign \( + \).
Step 4: Construct the switching table.
The switching table for the above logic expression is as follows:
\[
\begin{array}{|c|c|c|}
\hline
S_1 & S_2 & L
\hline
0 & 0 & 0
0 & 1 & 1
1 & 0 & 1
1 & 1 & 0
\hline
\end{array}
\]
Step 5: Interpret the results.
- When both switches are off (\( S_1 = 0, S_2 = 0 \)), the output is off (\( L = 0 \)).
- When \( S_1 = 0 \) and \( S_2 = 1 \), the output is on (\( L = 1 \)).
- When \( S_1 = 1 \) and \( S_2 = 0 \), the output is on (\( L = 1 \)).
- When both switches are on (\( S_1 = 1, S_2 = 1 \)), the output is off (\( L = 0 \)).
Final Answer: \[ L = (S_1 \cdot S_2') + (S_1' \cdot S_2) \]
Solve the following assignment problem for minimization :
Find x if the cost of living index is 150 :