Express the following in the form \(\frac{p }{ q}\) , where p and q are integers and q ≠ 0.
(i) 0.6(ii) 0.47 (iii) 0.001.
(i) \(\overline{0.6}\) = 0.666....
One digit 6 is repeating. We multiply it with 10 on both sides.
10x = \(\overline{6.6}\) ⇒ 10x = 6 + x
⇒ 10x - x = 6 ⇒ 9x = 6 ⇒ x = \(\frac{6}{9}\) = \(\frac{2}{3}\)
(ii) \(\overline{0.47}\)= 0.4777....
One digit is repeating. We multiply it with 10 on both sides.
∴ 10x = 4.7= 4.3 + .47 = 4.3 + x
⇒ 9x = 4.3 ⇒ x = \(\frac{4.3}{9}\) =\(\frac{43}{90}\)
(iii) 0.001= x = 0.001
Here three digits repeats; we multiply with 1000.
∴ 1000x = \(\overline{1.001}\)= 1000x = 1 + x
⇒ 1000x - x = 1 ⇒ 999x = 1
⇒ x = \(\frac{1}{999}\)
Write the following in decimal form and say what kind of decimal expansion each has :
(i) \(\frac{36}{100}\) (ii) \(\frac{1}{11}\) (iii) \(4\frac{1}{8}\)
(iv) \(\frac{3}{13}\) (v) \(\frac{2}{11}\) (vi) \(\frac{329}{400}\)
You know that \(\frac{1}{7}\) = 0142857_ . . Can you predict what the decimal expansions of \(\frac{2}{7},\frac{3}{7},\frac{4}{7},\frac{5}{7},\frac{6}{7}\) are, without actually doing the long division? If so, how? [Hint : Study the remainders while finding the value of 1/7 carefully.]
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
