Question

Explain the following nitration reaction:

• A.
• B.
• C.
• D.

Hint:

Electron-donating groups like methoxy (\( \text{OMe} \)) activate the ortho- and para-positions of the benzene ring, while electron-withdrawing groups like nitro (\( \text{NO}_2 \)) deactivate the meta-position.

Answer 1

The Correct Option is C

Step 1: Understanding the reactivity of the methoxy group.
The methoxy group (\( \text{OMe} \)) is an electron-donating group, which activates the benzene ring, making the ortho- and para-positions more reactive towards electrophilic substitution reactions like nitration.
Step 2: The role of the bromine group.
Bromine (\( \text{Br} \)) is also an electron-donating group, but less so compared to methoxy. The presence of both methoxy and bromine on the ring causes the nitration to occur predominantly at the ortho- and para- positions relative to both groups.
Step 3: Resulting substitution products.
As a result, the nitro group (\( \text{NO}_2 \)) is substituted at both the ortho- and para-positions relative to the methoxy group and bromine group on the benzene ring.
Conclusion:
Both the ortho- and para-positions to the methoxy group and bromine are activated, leading to substitution at these positions.