Molar Conductivity (\( \Lambda_m \)): It is the conductivity of an electrolyte solution per unit concentration: \[ \Lambda_m = \kappa \cdot \frac{1000}{C}, \] where \( \kappa \) is the conductivity and \( C \) is the molarity of the solution.
Calculation: 1. Conductivity (\( \kappa \)): \[ \kappa = \frac{\text{Cell constant}}{\text{Resistance}} = \frac{1.29}{480} = 0.0026875 \, \text{S cm}^{-1}. \] 2. Molar conductivity (\( \Lambda_m \)): \[ \Lambda_m = 0.0026875 \cdot \frac{1000}{0.02} = 134.375 \, \text{S cm}^2 \text{mol}^{-1}. \]

If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]