Step 1: Use substitution method
Let \( u = x^2 \Rightarrow du = 2x dx \Rightarrow x dx = \frac{1}{2} du \)
Step 2: Substitute and integrate
\[ \int x e^{x^2} dx = \int e^u \cdot \frac{1}{2} du = \frac{1}{2} \int e^u du = \frac{1}{2} e^u + C \] \[ \Rightarrow \frac{1}{2} e^{x^2} + C \]
The integral $ \int_0^1 \frac{1}{2 + \sqrt{2e}} \, dx $ is:
Find the area of the region (in square units) enclosed by the curves: \[ y^2 = 8(x+2), \quad y^2 = 4(1-x) \] and the Y-axis.
The scientist's theory was initially met with _________, but later gained widespread acclaim after consistent experimental validation.