Question:

Evaluate the infinite series: \[ 1 + \frac{1}{3} + \frac{1.3}{3.6} + \frac{1.3.5}{3.6.9} + \dots \text{ to } \infty = \]

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For infinite series involving factorial and double factorial patterns, recognize standard summation results to quickly evaluate their limits.
Updated On: Mar 25, 2025
  • \( \sqrt{5} \)
  • \( \sqrt{6} \)
  • \( \sqrt{15} \)
  • \( \sqrt{3} \)
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The Correct Option is D

Solution and Explanation

The given series is: \[ S = 1 + \frac{1}{3} + \frac{1.3}{3.6} + \frac{1.3.5}{3.6.9} + \dots \text{ to } \infty. \] Step 1: Identifying the pattern Observing the general term: \[ T_n = \frac{1 \cdot 3 \cdot 5 \cdots (2n-1)}{3 \cdot 6 \cdot 9 \cdots (3n)}. \] This is a standard series expansion for the function: \[ \sum_{n=0}^{\infty} \frac{(2n-1)!!}{(3n)!!}. \] From known mathematical results, the sum of the given infinite series converges to: \[ \sqrt{3}. \] Step 2: Conclusion Thus, the given series evaluates to: \[ \boxed{\sqrt{3}}. \]
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