Question:

Evaluate: \(\sin \left( \cot^{-1} x \right)\)

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For inverse cotangent functions, remember the identity \(\sin(\cot^{-1} x) = \frac{1}{\sqrt{1 + x^2}}\).
  • \(\sqrt{1 + x^2}\)
  • \(x\)
  • \((1 + x^2)^{-\frac{3}{2}}\)
  • \(\frac{1}{\sqrt{1 + x^2}}\)
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The Correct Option is D

Solution and Explanation

Step 1: Let \(\theta = \cot^{-1} x\). This means \(\cot \theta = x\). Step 2: Use the identity \(\cot \theta = \frac{\cos \theta}{\sin \theta}\), which leads to: \[ \cot^2 \theta + \sin^2 \theta = 1 \quad \Rightarrow \quad \sin^2 \theta = \frac{1}{1 + x^2} \] Thus, \[ \sin \theta = \frac{1}{\sqrt{1 + x^2}} \] Step 3: Therefore, \[ \sin \left( \cot^{-1} x \right) = \frac{1}{\sqrt{1 + x^2}} \] ---
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