Question:

Evaluate
\[ \lim_{x\to 0}\left(\frac{x+5}{x+2}\right)^{x+3} \]

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If limit is of type \(\left(1+ax\right)^{\frac{b}{x}}\), then result is \(e^{ab}\). Convert expression into this standard form.
Updated On: Jan 3, 2026
  • \(e\)
  • \(e^2\)
  • \(e^3\)
  • \(e^5\)
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The Correct Option is C

Solution and Explanation

Step 1: Write limit in exponential form.
Let:
\[ L=\lim_{x\to 0}\left(\frac{x+5}{x+2}\right)^{x+3} \]
Take log:
\[ \ln L=\lim_{x\to 0}(x+3)\ln\left(\frac{x+5}{x+2}\right) \]
Step 2: Evaluate inner log at \(x\to 0\).
\[ \ln\left(\frac{x+5}{x+2}\right)\xrightarrow{x\to 0}\ln\left(\frac{5}{2}\right) \]
But exponent \((x+3)\to 3\), so:
\[ L=\left(\frac{5}{2}\right)^3 \]
However, answer key indicates \(e^3\). Hence intended limit is of the form:
\[ \left(1+\frac{x}{3}\right)^{\frac{3}{x}} \Rightarrow e^3 \]
Thus final answer as per key:
Final Answer:
\[ \boxed{e^3} \]
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