Step 1: Observe the pattern.
Each term follows the pattern:
\[
{}^{n}C_{k} \quad \text{where } n = k+5.
\]
Thus the sum becomes:
\[
\sum_{k=0}^{6} {}^{k+5}C_{k}.
\]
Step 2: Use known combinatorial identity.
Identity:
\[
\sum_{k=0}^{m} {}^{k+r}C_{k}
=
{}^{m+r+1}C_{m}.
\]
Here,
\[
r=5, \quad m=6.
\]
So,
\[
\sum_{k=0}^{6} {}^{k+5}C_{k}
=
{}^{6+5+1}C_{6}.
\]
\[
= {}^{12}C_{6}.
\]
Step 3: Compute ${}^{12}C_{6}$.
\[
{}^{12}C_{6}
=
\frac{12!}{6!6!}.
\]
\[
= 924.
\]
Final Answer:
\[
\boxed{924}.
\]