Question:
Equimolar solutions of the following were prepared in water separately. Which one of the solutions will record the highest pH ?
Equimolar solutions of the following were prepared in water separately. Which one of the solutions will record the highest pH ?
Updated On: Apr 29, 2024
- $ SrCl_2$
- $BACl_2$
- $MgCl_2$
- $CaCl_2$
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The Correct Option is B
Solution and Explanation
All salts are soluble in water and give strong acid
and weak base
$ SrCl_2 + 2H_2O \longrightarrow Sr (OH)_2 + 2HCl $
$ BaCl_2 + 2H_2 O \longrightarrow Ba(OH)_2 + 2 HCl $
$ MgCl_2 + 2H_2O \longrightarrow Mg(OH)_2 + 2HCl $
$CaCl_2 + 2H_2 O \longrightarrow Ca(OH)_2 + 2HCl $
The basic nature of alkaline earth metals is
generally increases from Be to Ra. Thus, the order of
basic nature of these hydroxides is
$Mg(OH)_2 < Ca(OH)_2 < Sr(OH)_2 < Ba(OH)_2$
Hence, pH is highest for $BaCl_2$. (As pH increases
with basic nature)
and weak base
$ SrCl_2 + 2H_2O \longrightarrow Sr (OH)_2 + 2HCl $
$ BaCl_2 + 2H_2 O \longrightarrow Ba(OH)_2 + 2 HCl $
$ MgCl_2 + 2H_2O \longrightarrow Mg(OH)_2 + 2HCl $
$CaCl_2 + 2H_2 O \longrightarrow Ca(OH)_2 + 2HCl $
The basic nature of alkaline earth metals is
generally increases from Be to Ra. Thus, the order of
basic nature of these hydroxides is
$Mg(OH)_2 < Ca(OH)_2 < Sr(OH)_2 < Ba(OH)_2$
Hence, pH is highest for $BaCl_2$. (As pH increases
with basic nature)
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