Question:

Energy required to accelerate a car from $10 \,m / s$ to $20\, m / s$ compared with that required to accelerate it frem $0$ to $10 \,m / s$ is

Updated On: Aug 15, 2022
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The Correct Option is B

Solution and Explanation

$ K E_{1} =\frac{1}{2} m\left(v_{2}^{2}-v_{1}^{2}\right)$ $ \therefore K E_{1} =\frac{1}{2} m\left[(20)^{2}-(10)^{2}\right] $ $ \Rightarrow K E_{1} =\frac{1}{2} m(400-100) $ $ \Rightarrow K E_{1} =\frac{1}{2} m \times 300=150\, m$ ... (i) $ K E_{2} =\frac{1}{2} m\left[(10)^{2}-0\right] $ $\Rightarrow KE _{2}=\frac{1}{2} m \times 100=50 \,m$ ... (ii) From Eqs. (i) and (ii), we have $KE _{1}=3 KE _{2}$
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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.