Element A forms a tripositive ion, meaning its charge is \( +3 \). Element B forms a dinegative ion, meaning its charge is \( -2 \). To balance charges in a neutral compound, the total positive and negative charges must be equal. Let the number of A atoms be \( x \), and B atoms be \( y \): \[ 3x = 2y \] The smallest whole number solution is: \[ x = 2, \quad y = 3 \] So the chemical formula is \( A_3B_2 \), balancing \( 3 \times 2 = 6 \) positive and \( 2 \times 3 = 6 \) negative charges.
The correct option is (C): \(A_2B_3\)