Question:

Earth is revolving around the sun. If the distance of the earth from the sun is reduced to $1/4th$ of the present distance then the length of present day will be reduced by:

Updated On: Jun 7, 2022
  • $ \frac{1}{4} $
  • $ \frac{1}{2} $
  • $ \frac{1}{8} $
  • $ \frac{1}{6} $
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The Correct Option is C

Solution and Explanation

From Kepler's law
$T^{2} \propto R^{3}$
$\therefore \left(\frac{T_{1}}{T_{2}}\right)^{2} =\left(\frac{R_{1}}{R_{2}}\right)^{3}$
$\frac{T_{1}}{T_{2}} =\left(\frac{R_{1}}{R_{2}}\right)^{3 / 2}=\left(\frac{R}{R / 4}\right)^{3 / 2}$
$=(4)^{3 / 2}=(2)^{3}=8$
$\therefore T_{2} =\frac{T_{1}}{8}$
Hence, the length of the day is reduced by $\frac{1}{8}$.
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].