The given differential equation is:
\(\frac {dy}{dx} =(1+x^2)(1+y^2)\)
\(⇒\frac {dy}{1+y^2}=(1+x^2)dx\)
Integrating both sides of this equation, we get:
\(∫\frac {dy}{1+y^2}=∫(1+x^2)dx\)
\(⇒tan^{-1}y=∫dx+∫x^2dx\)
\(⇒tan^{-1}y=x+\frac {x^3}{3}+C\)
This is the required general solution of the given differential equation.
A battery of emf \( E \) and internal resistance \( r \) is connected to a rheostat. When a current of 2A is drawn from the battery, the potential difference across the rheostat is 5V. The potential difference becomes 4V when a current of 4A is drawn from the battery. Calculate the value of \( E \) and \( r \).
If \(\begin{vmatrix} 2x & 3 \\ x & -8 \\ \end{vmatrix} = 0\), then the value of \(x\) is:
A differential equation is an equation that contains one or more functions with its derivatives. The derivatives of the function define the rate of change of a function at a point. It is mainly used in fields such as physics, engineering, biology and so on.
The first-order differential equation has a degree equal to 1. All the linear equations in the form of derivatives are in the first order. It has only the first derivative such as dy/dx, where x and y are the two variables and is represented as: dy/dx = f(x, y) = y’
The equation which includes second-order derivative is the second-order differential equation. It is represented as; d/dx(dy/dx) = d2y/dx2 = f”(x) = y”.
Differential equations can be divided into several types namely