Question:
During electrolysis of dilute H$_2$SO$_4$ using platinum electrodes, the gas evolved at the anode is:
During electrolysis of dilute H$_2$SO$_4$ using platinum electrodes, the gas evolved at the anode is:
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In electrolysis of water or dilute acids, H$_2$ is evolved at the cathode and O$_2$ at the anode.
Updated On: Jul 1, 2025
- H$_2$ gas
- O$_2$ gas
- SO$_2$ gas
- SO$_3$ gas
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The Correct Option is B
Solution and Explanation
During electrolysis of dilute sulfuric acid using inert electrodes (like platinum), water is oxidized at the anode. The half-reaction at the anode is:
2H$_2$O $\rightarrow$ O$_2$ + 4H$^+$ + 4e$^-$
Hence, oxygen gas (O$_2$) is evolved at the anode.
2H$_2$O $\rightarrow$ O$_2$ + 4H$^+$ + 4e$^-$
Hence, oxygen gas (O$_2$) is evolved at the anode.
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