We are asked to find the domain of the function \( f(x) = \frac{x}{1 - |x|} \).
The domain of a function is the set of all possible input values (x-values) for which the function is defined.
For a rational function (a fraction), the function is undefined when the denominator is equal to zero.
In this case, the denominator is \( 1 - |x| \).
We set the denominator equal to zero and solve for x:
\[ 1 - |x| = 0 \]
Add \( |x| \) to both sides:
\[ 1 = |x| \]
The equation \( |x| = 1 \) means that x can be either 1 or -1.
\[ x = 1 \quad \text{or} \quad x = -1 \]
These are the values of x for which the function \( f(x) \) is undefined.
Therefore, the domain of the function is the set of all real numbers except for -1 and 1.
In set notation, this is written as \( \mathbb{R} - \{-1, 1\} \) or \( \mathbb{R} \setminus \{-1, 1\} \).
In interval notation, the domain is \( (-\infty, -1) \cup (-1, 1) \cup (1, \infty) \).
Comparing this with the given options:
The correct domain is R - {-1, 1}.
The function \( f(x) = \frac{x}{|x|} \) involves division by the absolute value of \( x \).
The domain of this function excludes \( x = 0 \), as division by zero is undefined.
Therefore, the domain is all real numbers except \( x = 0 \), or \(\mathbb{R} \setminus \{0\}\).
The function \( f(x) \) is defined for all values except \( x = 1 \) and \( x = -1 \), where it will result in an indeterminate form.
The correct answer is (D) : R - {-1, 1}
Let A be the set of 30 students of class XII in a school. Let f : A -> N, N is a set of natural numbers such that function f(x) = Roll Number of student x.
Give reasons to support your answer to (i).
Find the domain of the function \( f(x) = \cos^{-1}(x^2 - 4) \).
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
In an experiment to determine the figure of merit of a galvanometer by half deflection method, a student constructed the following circuit. He applied a resistance of \( 520 \, \Omega \) in \( R \). When \( K_1 \) is closed and \( K_2 \) is open, the deflection observed in the galvanometer is 20 div. When \( K_1 \) is also closed and a resistance of \( 90 \, \Omega \) is removed in \( S \), the deflection becomes 13 div. The resistance of galvanometer is nearly: