Question:
DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (Fig 9.15). If the area of the parallelogram is \(1470\) \(cm^2\) , AB = \(35\) \(cm\) and AD = \(49\) \(cm\), find the length of BM and DL.
DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (Fig 9.15). If the area of the parallelogram is \(1470\) \(cm^2\) , AB = \(35\) \(cm\) and AD = \(49\) \(cm\), find the length of BM and DL.
Updated On: Jan 11, 2024
Hide Solution
Verified By Collegedunia
Solution and Explanation
\(\text{Area of parallelogram }= \text{Base} ×\text{ Height }\)
= \(AB × DL\)
\(1470 = 35 × DL\)
\(DL=\frac{1470}{35}=42\;cm\)
\(Also, \;1470 = AD × BM\)
\(1470 = 49 × BM\)
\(BM=\frac{1470}{49}=30\;cm\)
Was this answer helpful?
1
0
Top Questions on Area Of A Parallelogram
- The area of the parallelogram, whose adjacent sides are given by the vectors \(\vec{a} = 2\hat{i} - \hat{j} + 5\hat{k}\) and \(\vec{b} = 2\hat{i} + \hat{j} + 2\hat{k}\), is:
- CUET (UG) - 2024
- Mathematics
- Area Of A Parallelogram
- Let \( \overrightarrow{OA} = \vec{a}, \overrightarrow{OB} = 12\vec{a} + 4\vec{b} \) and \( \overrightarrow{OC} = \vec{b} \), where \( O \) is the origin. If \( S \) is the parallelogram with adjacent sides \( OA \) and \( OC \), then\[\frac{\text{area of the quadrilateral OABC}}{\text{area of } S}\]is equal to ___.
- JEE Main - 2024
- Mathematics
- Area Of A Parallelogram
- Let \[ S = \{(x, y) \in \mathbb{R} \times \mathbb{R} : x \geq 0, y \geq 0, y^2 \leq 4x, y^2 \leq 12 - 2x, \text{ and } 3y + \sqrt{8}x \leq 5\sqrt{8}\}. \] If the area of the region \( S \) is \( \alpha \sqrt{2} \), then \( \alpha \) is equal to:
- JEE Advanced - 2024
- Mathematics
- Area Of A Parallelogram
- Considering only the principal values of the inverse trigonometric functions, the value of \[ \tan\left( \sin^{-1}\left(\frac{3}{5}\right) - 2 \cos^{-1}\left(\frac{2}{\sqrt{5}}\right) \right) \] is:
- JEE Advanced - 2024
- Mathematics
- Area Of A Parallelogram
- If four vertices of a parallelogram are (-3,-1),(a,b),(3,3) and (4,3) taken in order,then the ratio of a and b is
- AP POLYCET - 2023
- Mathematics
- Area Of A Parallelogram
View More Questions
Questions Asked in CBSE Class VII exam
- ∆ ABC is right angled at A (Fig 9.16). AD is perpendicular to BC. If AB = \(5\) cm, BC = \(13\) cm and AC = \(12\) cm, Find the area of ∆ ABC. Also find the length of AD.
- CBSE Class VII
- Area of a Triangle
- (i) For any integer a, what is (–1) × a equal to?
(ii) Determine the integer whose product with (–1) is
(a) –22
(b) 37
(c) 0- CBSE Class VII
- Properties Of Multiplication Of Integers
- What letters of the English alphabet have reflectional symmetry (i.e., symmetry related to mirror reflection) about.
- a vertical mirror
- a horizontal mirror
- both horizontal and vertical mirrors
- CBSE Class VII
- Lines Of Symmetry For Regular Polygons
- In a class test (+3) marks are given for every correct answer and (–2) marks are given for every incorrect answer and no marks for not attempting any question. (i) Radhika scored 20 marks. If she has got 12 correct answers, how many questions has she attempted incorrectly? (ii) Mohini scores –5 marks in this test, though she has got 7 correct answers. How many questions has she attempted incorrectly?
- CBSE Class VII
- Properties Of Division Of Integers
- Find the value of:
(i) -4÷\(\frac{2}{3}\)
(ii) -\(\frac{3}{5}\)÷2
(iii) -\(\frac{4}{5}\)÷(-3)
(iv) -\(\frac{1}{8}\)÷\(\frac{3}{4}\)
(v) -\(\frac{2}{13}\)÷\(\frac{1}{7}\)
(vi) -\(\frac{7}{12}\)÷(-\(\frac{2}{13}\))
(vii) \(\frac{3}{13}\)÷(-\(\frac{4}{65}\))- CBSE Class VII
- Operations On Rational Numbers
View More Questions