Comprehension
Directions: In a marriage party, 278 guests were present. Twenty guests took Pepsi and Dew, 23 guests took Dew and Sprite, 21 guests took Pepsi and Sprite, and 9 guests took all three cold drinks (Pepsi, Sprite and Dew). It is also known that there were equal numbers of bottles of each of the three kinds (Pepsi, Dew and Sprite).
Question: 1
How many guests enjoyed Dew or Sprite but not Pepsi?
How many guests enjoyed Dew or Sprite but not Pepsi?
Updated On: Oct 13, 2024
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The Correct Option is
Solution and Explanation
Total number of guests = 278
So, x + y + z + 21 + 20 + 9 + 23 = 278
Or x + y + z = 205 --- (1)
As, there were equal numbers of bottles of each of the three kinds (Pepsi, Dew and Sprite), we have:
x + 21 + 9 + 20 = y + 21 + 9 + 23 = z + 20 + 23 + 9
Or, x + 50 = y + 53 = z + 52--- (2)
On solving Eq. (1) and (2), we get:
x = 70, y = 67 and z = 68
So, final Venn diagram is as below:
Number of guests who enjoyed Dew or Sprite but not Pepsi = 68 + 23 + 67 = 158
So, the correct answer is E.
So, x + y + z + 21 + 20 + 9 + 23 = 278
Or x + y + z = 205 --- (1)
As, there were equal numbers of bottles of each of the three kinds (Pepsi, Dew and Sprite), we have:
x + 21 + 9 + 20 = y + 21 + 9 + 23 = z + 20 + 23 + 9
Or, x + 50 = y + 53 = z + 52--- (2)
On solving Eq. (1) and (2), we get:
x = 70, y = 67 and z = 68
So, final Venn diagram is as below:
Number of guests who enjoyed Dew or Sprite but not Pepsi = 68 + 23 + 67 = 158
So, the correct answer is E.
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Question: 2
How many guests enjoyed Pepsi and Dew but not Sprite?
How many guests enjoyed Pepsi and Dew but not Sprite?
Updated On: Oct 13, 2024
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Hide Solution
Verified By Collegedunia
The Correct Option is
Solution and Explanation
Number of guests who enjoyed Pepsi and Dew but not Sprite = 70 + 20 + 68 = 158
The correct answer is E.
The correct answer is E.
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