Question:
Diborane ${(B2H6)}$ reacts independently with ${O_2}$ and ${H2O}$ to produce, respectively
Diborane ${(B2H6)}$ reacts independently with ${O_2}$ and ${H2O}$ to produce, respectively
Updated On: Jul 6, 2024
- ${HBO_2}$ and ${H3BO3}$
- ${ H3BO3}$ and ${B_2O_3 }$
- ${B_2O_3 }$ and ${ H_3BO_3}$
- ${B_2O_3 }$ and ${[BH_4]^{-} }$
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The Correct Option is C
Solution and Explanation
${B2H6 + 3H2O -> 2H3BO3 + 3H2 }$
${B2H6 + 302 -> B2O3 + 3H2O}$
${B2H6 + 302 -> B2O3 + 3H2O}$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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