Diameter, d = 10.5cm
Radius, r = \(\frac{10.5}{2}\) cm = 5.25 cm
Slant height, l = 10 cm
Curved surface area = \(\pi rl\)
\(= \frac{22}{7} × 5.25 × 10\)
= 165 cm²
Thus, curved surface area of the cone = 165 cm².
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?