(i) Slant height (l) of cone = 14 cm
Let the radius of the circular end of the cone be r.
We know, CSA (Curved surface area) of cone = \(\pi rl\)
\(\pi rl\) = 308
\(r = \frac{308 cm²}{\pi l}\)
\(r =\frac{ 308 cm²}{14 cm} \times \frac{7}{22}\)
= 7 cm
Therefore, the radius of the circular end of the cone is 7 cm.
(ii) Total surface area of cone = CSA of cone + Area of base
\(=\pi r (l + r)\)
= \(\frac{22}{7} \)× 7 cm × (7 cm + 14 cm)
= 22 cm × 21 cm
= 462 cm²
Therefore, the total surface area of the cone is 462 cm2 .
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.