Diameter of human eye lens is 2 mm. What will be the minimum distance between two points to resolve them, which are situated at a distance of 50 meter from eye.The wavelength of light is 5000 Å
For the aparture, limit of resolution –
\(\frac{y}{D}\geq \frac{\lambda}{d}\) \(\Rightarrow\)\(y\geq\frac{\lambda D}{d}\)
\(\Rightarrow\)\(y \geq\frac{5\times10^{-3}}{2\times10^{-3}}\times50\)\(\geq\)1.25 cm.
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec: