Question:

Density of $3\,M$ solution of $NaCl$ is $1.25 \,g/mL$ The mass of the solvent in the solution is

Updated On: Jun 23, 2023
  • $1075.4 \,g$
  • $10.745 \,g$
  • $10.754\, g$
  • $1074.5\, g$
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The Correct Option is D

Solution and Explanation

$d = {1.25\, g/mL}$, conc, of solution = 3 M
= 3 moles in one litre of the solution.
Molar mass of $ {NaCl = 23 + 35.5 = 58.5 \, g \,mol^{-1}}$
Volume of solution= 1 L = 1000 mL
Mass of solution = $d \times V$
= $ {1.25\, g mL^{-1} \times 1000\, mL}$
= 1250 g
Mass of solute (NaCl) = n $\times$ molar mass
= $ { 3 \times 58.5 : 175.5 \,g}$
Mass of solvent
= Mass of solution - mass of solute
= 1250 -175.5 = 1074.5 g
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