Question:
\(\dfrac{d}{dx}\!\left(\dfrac{1}{4}\sec4x\right)=\) ?
\(\dfrac{d}{dx}\!\left(\dfrac{1}{4}\sec4x\right)=\) ?
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For $\sec(kx)$, derivative is $k\,\sec(kx)\tan(kx)$.
Updated On: Oct 17, 2025
- \(\sec4x\cdot\tan4x\)
- \(\sec^{2}4x\)
- \(\tan^{2}4x\)
- \(\dfrac{1}{16}\sec4x\cdot\tan4x\)
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The Correct Option is A
Solution and Explanation
\[
\frac{d}{dx}\!\left(\frac14\sec4x\right)=\frac14\cdot (\sec4x\tan4x)\cdot 4=\sec4x\tan4x.
\]
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